construct a triangle ABC in which AB+AC =5.6cm BC=4cm and angle B=45 degree
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Answer:
1. Construct a line segment BC of 4cm
2. Construct a 45° angle at B
3. Take the length of PB as 5.6cm.
4. Join PC
5. Construct a bisector at PC. The line will meet BP at point A. Join AC
We get the required triangle.
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answer :-
Construct a line segment BC of 4.5cm
Construct a line segment BC of 4.5cm2. Construct a 45°
angle at B
angle at B3. Take the length of PB as 5.6cm.
angle at B3. Take the length of PB as 5.6cm.4. Join PC
angle at B3. Take the length of PB as 5.6cm.4. Join PC5. Construct a bisector at PC. The line will meet BP at point A. Join AC
angle at B3. Take the length of PB as 5.6cm.4. Join PC5. Construct a bisector at PC. The line will meet BP at point A. Join ACWe get the required triangle.
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