Construct a triangle ABC, in which AB +BC +AC = 13.5 cm, angle B = 45degree , angle C = 75degree
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Solution
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Given,
to construct a ΔABC where
BC=7cm,∠B=75∘ & AB+AC=13cm.
construction steps :-
(i) Draw a line segment BC = 7 cm as a base.
(ii) Now mark ∠B=75∘ and extend it till x.
(iii) Now, by taking radius 13 cm draw an arc from 'B' on the line of angle just projected.
(iv) Now mark it as 'D', & join C to D.
(v) Draw ⊥lar bisectors for DC and mark them as P & Q.
(vi) Now extend a line from 'B' to the ⊥lar bisector that cuts on C & D line.
(vii) Now mark that point as 'A'.
(viii) Thus, required ΔABC has been formed.
(ix) Now, try taking exactly 1/2 of the angle and mark an arc on B.
Conclusion :-
∴ The required ΔABC will BC = 7 cm,
∠B=45∘ & AB + AC = 13 cm is constructed
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