Question

Construct a triangle ABC in which AB
BC + CA = 10 cm. angle B = 60° and
angle C=30°​

Answer 1

Step 1: Draw a line segment PQ ( = AB + BC + CA ) = 10cm.

Step2: Draw an angle of 60° at P and an angle of 45° at Q.

Step 3: Bisect ∠P and ∠Q. Let the bisectors of ∠P and ∠Q intersect in A.

Step 4: Draw perpendicular bisector DE of AP which intersect PQ in B and FG of AQ which intersect PQ in C

Step.5: Join AB and AC. ∴ ΔABC is the required triangle