Question

construct a triangle ABC in which AB+BC+CA = 10cm. angle B= 60° and angle C= 45° .

Answer 1

(1) Construct BC = 6 cm

(2) Construct an angle of 60° at B on BC.

(3) Taking B as centre, with 9 cm radius, draw an arc , which cuts the ray of 60° angle, at X

(4) Join X & C

(5) Then draw perpendicular bisector of XC

(6) Wherever this perpendicular bisector intersects BX, name that point as A.

(7) Join A & C

So, tri ABC will be the required triangle.

Justification:

Since AC = AX ( as point ‘A’on perpendicular bisector remains equidistant from X & C )

But AX + AB = 9cm ( we constructed)

=> AC + AB = 9 cm