Question

construct a triangle abc in which ab+bc+ca=11.6cm and base angle are 45° and 60°​

Answer 1

Step-by-step explanation:

1. First make a line segment xy which is equal to ab+bc+ca=11.6 cm
2. Then from point x make an angle of 60°
3. Then from point y make an angle of 45°
4. Now Bisect the angles of 60° and 45° constructed by you.
5. Both bisected will met at a point mark it as point A.
6. Then now make perpendicular bisectors of both you angle bisectors of point 60° and 45°.
7. Then where the line segments of of perpendicular bisectors of both angle intersect at the sline segment xy are your point B and C respectively.