Construct a triangle ABC in which AC = AB = 4.5 cm and angle A = 90°. Draw a triangle similar to triangle ABC with its sides equal to (5/4)th of the corresponding sides of triangle ABC.
Answers
The following steps would show you how to construct it:
Step one: Draw a line segment AB=4.5 cm.
Step two: Using a protractor, draw ∠BAD=90°. Taking A as the center and radius 4.5 cm, draw an arc, intersecting AD at C. Join BC.
Step three: Draw any line segment AE, making an acute angle with AB and opposite to the vertex C. Taking A as the center and any radius, draw an arc, intersecting AE at F. Taking F as the center and radius AF, draw an arc, intersecting AE at G. Similarly, repeat the process 3 more times to get points H, I and J. Join BI.
Step four: Taking I as the center and any radius, draw an arc., intersecting AE and BI at K and L respectively. Taking J as the center and radius IK, draw an arc., intersecting AE at M. Taking M as the center and radius KL, draw an arc, intersecting previous arc at N. Join and extend JN, intersecting extended AB at O.
Step five: Taking B as the center and any radius, draw an arc., intersecting BA and BC at Q and R respectively. Taking O as the center and radius BQ, draw an arc., intersecting AO at S. Taking S as the center and radius QR, draw an arc, intersecting previous arc at T. Join and extend OT, intersecting AD at P.
Step six: ∆AOP is the required triangle.
Step-by-step explanation:
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