construct a triangle ABC in which angle B = 30 ° angle C = 90 ° and AB+BC+CA = 11 cm
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CONSTRUCTION OF ΔABC WITH ∠B = 30° ∠C = 90° AND AB+BC+CA = 11 CM: Draw a line segment PQ = 11 cm. Mark an angle 30° at P and 90° at
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Step-by-step explanation:
construct a line segment of 11 CM. draw angles of 30 & 90 on both the sides of line segment.bisect both the angles and produce such that thay meet each other.now draw the perpendicular bisector of each produced lines at where they meet the line segment join these to the intersection of both the produced lines.............
Hence it is a required triangle..
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