construct a triangle ABC in
which angle B = 30° , angle c = 90
and AB + BC+CA = 10 cm
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Step by step answer
- Draw a line segement PQ =11cm
- Mark an angle 30°at P and 90° at Q
- Bisect these angles .
- Let the angle bisectors meet at point A
- Draw perpendicular bisector to AP. Let bisector of AQ
- Let it intersect PQ at C
- Join AB and A
- ABC is our required triangle
Hope it help you
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