Construct a triangle ABC in which angle B = 30° , angle C = 90° and AB+BC+AC = 11 cm
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this may b the process
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saiffaiz2:
thank you so much
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CONSTRUCTION OF ΔABC WITH ∠B = 30° ∠C = 90° AND AB+BC+CA = 11 CM:
- Draw a line segment PQ = 11 cm.
- Mark an angle 30° at P and 90° at Q.
- Bisect these angles.
- Let the angle bisectors meet at point A.
- Draw perpendicular bisector to AP.
- Let it intersect PQ at B.
- Draw perpendicular bisector to AQ.
- Let it intersect PQ at C.
- Join AB and AC.
- ABC is our required triangle.
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