construct a triangle abc in which angle b 60degree , angle c 45 degree and ab+bc+ca 11cm write steps also. please please please
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Step 1: Draw a line segment PQ ( = AB + BC + CA ) = 11cm.
Step 2: Draw an angle of 60° at P and an angle of 45° at Q.
Step 3: Bisect ∠P and ∠Q. Let the bisectors of ∠P and ∠Q intersect in A.
Step 4: Draw perpendicular bisector DE of AP which intersect PQ in B and FG of AQ which intersect PQ in C.
Step 5: Join AB and AC.
∴ ΔABC is the required triangle.
I hope it will help you
Step 2: Draw an angle of 60° at P and an angle of 45° at Q.
Step 3: Bisect ∠P and ∠Q. Let the bisectors of ∠P and ∠Q intersect in A.
Step 4: Draw perpendicular bisector DE of AP which intersect PQ in B and FG of AQ which intersect PQ in C.
Step 5: Join AB and AC.
∴ ΔABC is the required triangle.
I hope it will help you
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