Math, asked by abhi456789, 4 months ago

Construct a triangle ABC in which angle B = 80 angle C =60AB +BC+CA=8.6​

Answers

Answered by aslamm1
0

Answer:

Solution :-

Step first : Draw a line segment BC = 6 cm.

Step second : construct angle of 60° at B on BC.

Step third : Taking B as centre with 9 cm radius draw an arc which cut the ray of 60° angle at X

Step fourth : join X and c

Step fifth : the draw perpendicular bisector of XC

Step six: wherever this perpendicular bisector intersection BX, name that point as a A

Step seven: Join A and C

Step eight : so ∆ ABC will be the required triangle.

justification :-

AC = AX ( as point A on perpendicular bisector ramains equidistant from X and

AX + AB =9 cm

AC + AB = 9cm

Step-by-step explanation:

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