Construct a triangle ABC in which angle B = 80 angle C =60AB +BC+CA=8.6
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Solution :-
Step first : Draw a line segment BC = 6 cm.
Step second : construct angle of 60° at B on BC.
Step third : Taking B as centre with 9 cm radius draw an arc which cut the ray of 60° angle at X
Step fourth : join X and c
Step fifth : the draw perpendicular bisector of XC
Step six: wherever this perpendicular bisector intersection BX, name that point as a A
Step seven: Join A and C
Step eight : so ∆ ABC will be the required triangle.
justification :-
AC = AX ( as point A on perpendicular bisector ramains equidistant from X and
AX + AB =9 cm
AC + AB = 9cm
Step-by-step explanation:
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