Question

construct a triangle ABC in which Angle B is 30° angle C is 60° and BC is 3.8 CM​

Answer 1

Answer:ΔABC is constructed AB = 3.8 cm ∠B = 60° & AD = 3.6 cm

Step-by-step explanation:

Step 1 : Draw a line segment AB = 3.8 cm using ruler

Step 2 : Draw an angle of 60 deg at B using protector

Step 3 : Draw an arc of radius = 3.6 cm , taking A as center such that in intersect angle drawn in step 2 at D

Step 4 : Take Length = BD & cut the angle drawn at B in opposite side of D at C.

Step 5 : Join AC

ΔABC is constructed

to Draw AB' = (4/3) AB

Step 1 : Extend AB

Step 2: Draw an acute angle at A

Step 3 : Take 4 Equal segment of angle drawn one by one

Step 4 : join 3rd point with B

Step 5 : Draw a line parallel to line drawn in Step 4 such that it passed through 4th point and intersect extended AB at B'

AB' = (4/3)AB