Question

Construct a triangle ABC in which /B-60 , /C-45 and the perimeter of the triangle is 10 cm
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Answer 1

$\huge\frak{Answer}$

Steps of Construction :

• Draw a line segment, say XY equal to BC + CA + AB = 10 cm.
• Make angle LXY equal to 60o and angle MYX equal to 45o.
• Bisect LXY and MYX. ...
• Draw perpendicular bisector PQ of AX and RS of AY.
• Let PQ intersect XY at B and RS intersect XY at C.
• Join AB and AC.
• ABC is the required triangle.

Answer 2

Answer:

1. Draw a line segment, say XY equal to BC + CA + AB = 10 cm.

2. Make angle LXY equal to 60o and angle MYX equal to 45°.

3. Bisect LXY and MYX.

4. Draw perpendicular bisector PQ of AX and RS of AY.

5. Let PQ intersect XY at B and RS intersect XY at C.

6. Join AB and AC.

7. ABC is the required triangle.

$thanks$