Construct a triangle ABC, in which base BC=3 cm, angle B=30 degree and AB+AC=5.2 cm
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Answered by
44
Even if I draw and give it to you, it won't help because construction can't really be copied. If you want your triangle to be correct, you have to make it yourself with measurements.
I can help you a bit though, draw a 3cm line segment (name it BC) , on the point B construct an angle of 30°. (name it angle PBC) . Cut the line segment BD = 5.2 cm on ray BP. Join the line DC and draw perpendicular bisector XQ of DC. Let it intersect BP at the point A. join AC. TADA!! follow the instructions :)
I can help you a bit though, draw a 3cm line segment (name it BC) , on the point B construct an angle of 30°. (name it angle PBC) . Cut the line segment BD = 5.2 cm on ray BP. Join the line DC and draw perpendicular bisector XQ of DC. Let it intersect BP at the point A. join AC. TADA!! follow the instructions :)
Answered by
86
I explain the steps of construction
♦Draw a line segment BC=3 cm
♦Draw angle B = 30° and produce it to X.
♦At centre B,take radius 5.2 and draw an arc to meet BX at D.
♦Now,join CD
♦Draw the perpendicular bisectors of CD and BD.
♦Join the perpendicular bisectors
♦The perpendicular bisectors meet BD at A.
♦Join AC.
♦Triangle ABC is required triangle to construct.
please mark as brainliest answer
♦Draw a line segment BC=3 cm
♦Draw angle B = 30° and produce it to X.
♦At centre B,take radius 5.2 and draw an arc to meet BX at D.
♦Now,join CD
♦Draw the perpendicular bisectors of CD and BD.
♦Join the perpendicular bisectors
♦The perpendicular bisectors meet BD at A.
♦Join AC.
♦Triangle ABC is required triangle to construct.
please mark as brainliest answer
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