Construct a triangle ABC in which base BC=4.5 cm, angle B= 60 degree and AB+AC=7.1 cm
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Answer:
Justification:-
After drawing ΔDBC with BC=4.5cm, ∠B=45
o
and DB=8cm. The perpendicular bisector of DC is drawn and it intersects DB at A.
So, we get AC=AD
BD=8cm
⇒BA+AD=8cm
⇒AB+AC=8cm
Hence ΔABC is the required triangle.
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