Construct a triangle ΔABC, in which BC=3.6cm, ∠∠B = 60° and AB + AC= 5.4 cm
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Step 1: Draw a line segment BC = 3.6 cm. Step 2: At the point B, draw ∠XBC = 60°. Step 3: Draw an arc which intersects XB at point D form point B and with radius 4.8 cm Step 4: Join DC. Step 5: Draw a perpendicular bisector of DC which intersects DB at A. Step 6: Join AC. Hence, △ABC is the required triangle. Read more on Sarthaks.com - https://www.sarthaks.com/616865/construct-a-abc-in-which-bc-3-6-cm-ab-ac-4-8-cm-and-b-60
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