Construct a triangle ABC in which BC=4.5 cm,∠ = 45° and AB-AC= 2.5 cm.
PLEASE INCLUDE JUSTIFICATION
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Answer:
After drawing ΔDBC with BC=4.5cm, ∠B=45
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and DB=8cm. The perpendicular bisector of DC is drawn and it intersects DB at A.
So, we get AC=AD
BD=8cm
⇒BA+AD=8cm
⇒AB+AC=8cm
Step-by-step explanation:
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