Question

construct a triangle ABC in which BC=4.5 CM , angle N =45° and AB-AC=2.5 cm

Answer 1

We have to construct a triangle with the given data as-

Step-1: Draw the base line segment QR= 6 cm.

Step-2 : From Q, draw an angle of using compass, say ∠XQR.

Step-3 :Extend the line QX in the opposite direction as well to T. Cut a line segment QS of 2 cm from the line segment QT extended in the opposite side of line segment XQ. Now join the point to R in order to get SR.

Step-4 : Draw perpendicular bisector AB of line segment SR. Let it intersect QX at point P. Join PQ, PR.

Thus ΔPQR is the required triangle.