construct a triangle ABC in which BC=4.5 CM , angle N =45° and AB-AC=2.5 cm
Answers
Answered by
6
We have to construct a triangle with the given data as-
Step-1: Draw the base line segment QR= 6 cm.
Step-2 : From Q, draw an angle of using compass, say ∠XQR.
Step-3 :Extend the line QX in the opposite direction as well to T. Cut a line segment QS of 2 cm from the line segment QT extended in the opposite side of line segment XQ. Now join the point to R in order to get SR.
Step-4 : Draw perpendicular bisector AB of line segment SR. Let it intersect QX at point P. Join PQ, PR.
Thus ΔPQR is the required triangle.
Step-1: Draw the base line segment QR= 6 cm.
Step-2 : From Q, draw an angle of using compass, say ∠XQR.
Step-3 :Extend the line QX in the opposite direction as well to T. Cut a line segment QS of 2 cm from the line segment QT extended in the opposite side of line segment XQ. Now join the point to R in order to get SR.
Step-4 : Draw perpendicular bisector AB of line segment SR. Let it intersect QX at point P. Join PQ, PR.
Thus ΔPQR is the required triangle.
Attachments:
Similar questions