Question

construct a triangle ABC in which BC=4•5cm,<B=45°,and AB-AC=2•5cm.​

Answer 1

Answer:

Answer

Justification:-

After drawing ΔDBC with BC=4.5cm, ∠B=45

o

and DB=8cm. The perpendicular bisector of DC is drawn and it intersects DB at A.

So, we get AC=AD

BD=8cm

⇒BA+AD=8cm

⇒AB+AC=8cm

Hence ΔABC is the required triangle.