construct a triangle ABC in which bc = 4.7 cm ab + ac = 8.2 cm and angle c =60 degree
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Answered by
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Answer:
1. Construct a line segment BC of 4.5cm
2. Construct a 45o angle at B
3. Take the length of PB as 5.6cm.
4. Join PC
5. Construct a bisector at PC. The line will meet BP at point A. Join AC
We get the required triangle.

Answered by
4
Step-by-step explanation:
Given : In ΔABC, BC= 4.7 cm, AB + AC = 8.2 cm and ∠C= 60°.
Required : To construct ΔABC.
Steps of construction:
1. Draw BC = 4.7 cm.
2. Draw ∠BCX
3. From ray CX, cut off CD = 8.2
4. Join BD.
5. Draw the perpendicular bisector of BD meeting CD at A.
6. Join AB to obtain the required triangle ABC.
Justification :
∵ A lies on the perpendicular bisector BD, therefore
AB = AD
Now, CD = 8.2 cm ⇒ AC + AD = 8.2 cm ⇒ AC + AB = 8.2 cm
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