Question

construct a triangle abc in which BC =4.7 CM angle b=60 degree and AB + BC =8.2 CM

Answer 1

Given : In ΔABC, BC= 4.7 cm, AB + AC = 8.2 cm and ∠C= 60°.
Required : To construct ΔABC.

Steps of construction: 

1. Draw  BC = 4.7 cm.

2. Draw ∠BCX 

3. From ray CX, cut off CD = 8.2 

4. Join BD. 

5. Draw the perpendicular bisector of BD meeting CD at A. 

6. Join AB to obtain the required triangle ABC.  

Justification :

∵ A lies on the perpendicular bisector BD, therefore 

AB = AD 

Now, CD = 8.2 cm ⇒  AC + AD = 8.2 cm ⇒  AC + AB =  8.2 cm 

Answer 2

draw a line and make an arc of side bc = 4.7cm
next construct an angle of 60degree at b and
make an arc of AB =8.2 - 4 7 = 3.5cm from B .
U will get point A and then join AC.....
so ABC is required triangle.....