Construct a triangle ABC in which BC=4.8cm, Angle B =60,AB+AC=8cm
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Its very easy babes draw a line segment of 4.8 and mark it as BC then from B take 60 degrees witg protactor and mark a point on ot then then take compass with radius 4 cm and draw an arc from B and again take 4cm from C and draw an arc join the poibts u will get the following construction plzzzzzzzzzzZZZZZZZZ MARK AS BRAINLIEST
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at first draw BC of length 4.8 CM
then with B as centre construct an angle of 60°
extend the arm till X
now mark a point P of length 8 cm on BX
join c and p
now draw a perpendicular bisector of CP
the perpendicular bisector must be extended to BP
say it cut BP at point A join AC
you have required triangle ABC
then with B as centre construct an angle of 60°
extend the arm till X
now mark a point P of length 8 cm on BX
join c and p
now draw a perpendicular bisector of CP
the perpendicular bisector must be extended to BP
say it cut BP at point A join AC
you have required triangle ABC
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