Question

construct a triangle ABC in which BC = 5 cm, angle B = 45 degrees and AB + CA = 8 cm. Also show the steps of construction.​

Answer 1

Step-by-step explanation:

i)Draw base BC of length 8 cm

.Now, let's draw ∠B=45

∘

.Let the ray be BX

.Open the compass to length AB−AC=3.5cm.

So, BD will be above line BC

From point B as center, cut an arc on ray BX.

Let the arc intersect BX at D

4.Join CD

5.Now, we will draw perpendicular bisector of CD

6.Mark point A where perpendicular bisector intersects BD

7.Join AC