Question

Construct a triangle ABC in which BC = 5 cm , angle B = 75 0 and sum of two sides is 9
cm .

Answer 1

Step-by-step explanation:

Step-1 : Draw a line BC = 5 cm. Using Protractor, mark angle 75° at B.

Step-2 : Draw a line BD = 9cm so that DBC = 75°. Join CD. ...

Let this perpendicular bisector meet BD and CD at A and E respectively.

Step-3 : Join AC . ΔABC is constructed as per the requirement.

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