Question

Construct a triangle ABC, in which BC = 5 cm,
∠B = 30° and AC – AB = 2 cm.​

Answer 1

Answer:

1. Draw a line BC=5cm

2. Construct 30 at B. Extend BP.

3. Take 2cm on a compass and cut an arc on BP. Join CX.

4. Take a perpendicular bisector of CX. It intersects with BP at A.

5. Join AC

Answer 2

The construction of ∆ABC is attached, in which BC = 5 cm, ∠B = 30° and AC – AB = 2 cm.

Given:

• ∆ABC
• BC=5 cm
• Angle B= 30°
• AC-AB= 2 cm

To find:

• Construction of triangle with give specification.

Solution:

Concept to be used:

As AC > AB, The arc of difference of both sides will be made towards downward direction of angle line.

Steps of construction:

1. Draw a line BC=5cm with the help of pencil and scale.
2. Make 30° angle at B with the help of protector or compass.
3. Extends the line below base line BC.
4. Make an arc of 2 cm from B,let the point is P.
5. Draw CP.
6. Draw perpendicular bisector of CP, it intersects the line BP in upward direction, let the point is A.
7. Draw line AC.
8. Thus, Construction of ∆ABC is done.

Verification:

On measurements

AC= 3.7 cm

AB= 1.7 cm

AC-AB= 3.7-1.7= 2 cm

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