Question

Construct a triangle ABC in which BC=5cm, Angle B=60,AB+AC=7.5

Answer 1

I will explain the steps. Follow them and you can make the triangle.

1.  Draw line segment BC horizontally of length = 5 cm.
2.  At B using protractor draw a line above BC making an angle of 60°.
3.  Draw an arc with B as a center and with a radius of 7.5 to cut this line.
    Mark the point as D. So BD=7.5. 
4.  Join C and D.  Draw the perpendicular bisector of CD using the standard procedure.  Draw an arc upside and below CD with center as C and D one after another. Join the two points of Intersections.

5. The point of intersection of the perpendicular bisector of CD and the line BD gives the point A.  
6. Join  AC.

Done.

Answer 2

Steps of Construction

STEP-1:- Draw a ray BX and cut off a line segment

BC =5cm from it

STEP-2:-Construct ∠XBY = 60°

STEP-3:- From BY cut off a line segment BD = 7.5 cm

STEP-4:- join cd

STEP-5:-raw the perpendicular bisector of CD, intersecting BY at a point A. 

STEP-6:- join AC

Required ABC triangle is obtained.