Question

construct a triangle abc in which bc=5cm b=20° and ab-ac=2.5cm. No wrong answers or will be reported.

Answer 1

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The steps of construction to be followed:

Step 1: Draw a line segment BC = 8cm and make an angle of

at point B i.e.,

XBC

Step 2: Now, cut the line segment BD = 3.5 cm on ray BX. i.e.

.

Step 3: Join CD and draw a perpendicular bisector of CD i.e., PQ.

XCD 45

Step 4: Let the perpendicular bisector of CD intersects BX at point A. Then,

atep 3

Step 5: Join AC, to get the required triangle