Question

construct a triangle ABC in which BC=5cm,CB_75° and AB+AC=9cm​

Answer 1

Answered

CONSTRUCT a triangle ABC in which bc=5 cm, angleb=75% and AB+AC=9 CM

Asked by B.lakhnotra26 | 10th Mar, 2019, 01:02: PM

Expert Answer:

Step-1 : Draw a line BC = 5 cm. Using Protractor, mark angle 75° at B.

Step-2 : Draw a line BD = 9cm so that begin mathsize 12px style angle end styleDBC = 75°. Join CD. Draw a perpendicular bisector to line segment CD.

Let this perpendicular bisector meet BD and CD at A and E respectively

Step-3 : Join AC . ΔABC is constructed as per the requirement.

Proof:- Δ AEC and ΔAED are congruent. Hence AC = AD. But as per construction AB+AD = 9 cm. Hence AB+AC = 9 cm