Construct a triangle ABC in which BC = 6 cm, B = 60° and AB + AC = 10 cm.
Answers
Answer:
Step-by-step explanation:
Step's of construction
(1) Draw BC = 6 cm.
(2) Construct /_ CBX = 60°.
(3) Along BX , set off BP = 9 cm.
(4) Join CP
(5) Draw the perpendicular bisector of CP tp intersect BP at A .
(6) Join AC. Then, ∆ABC is the required triangle.
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Step-by-step explanation:
Given : Triangle ABC in which B=60° , BC=6cm and AB+AC=10 cm
To Find : construct triangle
Solution:
Step 1: Draw a line segment BC 6 cm.
Step 2 : Draw ∠B =60° using protractor and draw a ray BX.
Step 3 : With Center B and radius 10 cm, make an arc which intersects BX at E.
Step 4 : Join CE
Step 5 : Draw a perpendicular bisector of segment CE it intersect the ray BX at point A.
Step 6 : Join C to A
Triangle is constructed
As A is on perpendicular bisector of CE hence AE = AC
AB + AC = AB + AE = AE = 10 cm
Method to Draw perpendicular bisector :
Using suitable compass width and taking C and E as center draw arcs both sides intersecting each other.
Draw a line passing through intersection point of arcs and intersecting BE at A
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