Construct a triangle ABC in which BC = 6cm AB-AC= 1.2cm,B = 60°.
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Draw a line segment BC = 6 cm.
With B as centre, draw ∠TBC = 60°.
From BT, cut BS = 1.2 cm.
Join S and C.
Draw perpendicular bisector of SC which cut BT at A.
Join AC.
Thus, ABC is the required triangle
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