Question

Construct a triangle ABC in which BC = 6cm and angle B = 40 degree and angle C= 110 degree

Answer 1

firstly , 1.draw a line segment BC of length 6cm
2. At point B , making an angle of 40° nd draw an arc 3. then at point C , making an 110° and draw an arc it will intersect at point A 4. then join AB to AC
5. our triangle ABC is complete

Answer 2

ΔABC is constructed  in which BC = 6cm and angle B = 40 degree and angle C= 110 degree

Step-by-step explanation:

Step 1 : Draw a line segment BC = 6 cm using ruler

Step 2: Draw an angle of 40° at B on BC using Protector

Step 3 : Draw an angle of 60° at C on BC  using Protector such that intersect angle drawn in step 2 at A

ΔABC is constructed

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