Construct a Triangle ABC in which Bc-6cm Angle B-60 and (Ab+BC)=9 cm.Measure AB. and BC .Justify your answer.
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Solution
Step first : Draw a line segment BC = 6 cm .
Step second : Construct angle of 60° at B on BC
Step third : Taking B as centre with 9 cm radius draw an arc which cut the ray of 60° angle at X .
Step fourth : Join X and C
Step fifth : The draw perpendicular bisector of XC
Step Sixth : Wherever this perpendicular bisector intersection BX , name that point as a A
Step Seventh : Join A and C
Step eighth : So triangle ABC we will the required triangle .
Justification :
AC = AX ( as point A on perpendicular bisector remains equidistant from X and
AX + AB = 9 cm
AC + AB = 9 cm
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