Construct a triangle ABC in which BC = 7.5 cm, ∠C = 45° and AB – AC = 4 cm. Justify your construction.
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Answer:
1. Draw the base BC 7.5 cm and at point B make
an angle say XBC of 45 degree.
2. Cut line segment BD equal to AC - BC (4 cm)
from line BX extended on opiate side of BC.
3. Join DC and draw perpendicular bisector, say
PQ of DC.
4. Let PQ intersect BX at A. Join AC.
Thus, ABC is the required triangle.
Step-by-step explanation:
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