construct a triangle ABC in which bc =7.5cm, angle b =45 degree, the difference between between the other two sides is 4cm.
Answers
Answered by
50
Answer:
1. Draw the base BC 7.5 cm and at point B make an angle say XBC of 45 degree.
2. Cut line segment BD equal to AC - BC (4 cm) from line BX extended on opiate side of BC.
3. Join DC and draw perpendicular bisector, say PQ of DC.
4. Let PQ intersect BX at A. Join AC.
Thus, ABC is the required triangle.
Step-by-step explanation:
sharmaaryanu6432432w:
hope it helps you if it helps you then mark my answer as brainlist
Bro pq kha see a gye
Answered by
14
Answer:
1. Draw the base BC 7.5 cm and at point B make
an angle say XBC of 45 degree.
2. Cut line segment BD equal to AC - BC (4 cm)
from line BX extended on opiate side of BC.
3. Join DC and draw perpendicular bisector, say
PQ of DC.
4. Let PQ intersect BX at A. Join AC.
Thus, ABC is the required triangle.
Similar questions