Question

Construct a triangle ABC in which BC= 7 cm, AngleB= 60° and AC - AB = 3 cm. Write the steps of construction.
Answer:​

Answer 1

Answer:

here is your answers

Step-by-step explanation:

Steps of Construction :

Steps of Construction :1 Draw a line segment BC=7 cm

Steps of Construction :1 Draw a line segment BC=7 cm2 Construct ∠CBX=60∘

Steps of Construction :1 Draw a line segment BC=7 cm2 Construct ∠CBX=60∘3 Draw OB⊥BX intersecting the perpendicular bisector of BC at O.

Steps of Construction :1 Draw a line segment BC=7 cm2 Construct ∠CBX=60∘3 Draw OB⊥BX intersecting the perpendicular bisector of BC at O.4 With O as centre and radius OB or OC draw a circle.

Steps of Construction :1 Draw a line segment BC=7 cm2 Construct ∠CBX=60∘3 Draw OB⊥BX intersecting the perpendicular bisector of BC at O.4 With O as centre and radius OB or OC draw a circle.5 Cut DN=3.7 cm

Steps of Construction :1 Draw a line segment BC=7 cm2 Construct ∠CBX=60∘3 Draw OB⊥BX intersecting the perpendicular bisector of BC at O.4 With O as centre and radius OB or OC draw a circle.5 Cut DN=3.7 cm6 Through N draw ⊥ on DN intersecting the circle at the point A and A′.

Steps of Construction :1 Draw a line segment BC=7 cm2 Construct ∠CBX=60∘3 Draw OB⊥BX intersecting the perpendicular bisector of BC at O.4 With O as centre and radius OB or OC draw a circle.5 Cut DN=3.7 cm6 Through N draw ⊥ on DN intersecting the circle at the point A and A′.7 Join AB,AC and A′B,A′C

Steps of Construction :1 Draw a line segment BC=7 cm2 Construct ∠CBX=60∘3 Draw OB⊥BX intersecting the perpendicular bisector of BC at O.4 With O as centre and radius OB or OC draw a circle.5 Cut DN=3.7 cm6 Through N draw ⊥ on DN intersecting the circle at the point A and A′.7 Join AB,AC and A′B,A′C8 ∴ΔABC and ΔA′BC are the required triangles

Steps of Construction :1 Draw a line segment BC=7 cm2 Construct ∠CBX=60∘3 Draw OB⊥BX intersecting the perpendicular bisector of BC at O.4 With O as centre and radius OB or OC draw a circle.5 Cut DN=3.7 cm6 Through N draw ⊥ on DN intersecting the circle at the point A and A′.7 Join AB,AC and A′B,A′C8 ∴ΔABC and ΔA′BC are the required trianglesHence, the number of possible triangles =2.

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