Construct a triangle ABC in which BC = 7 cm,
angleB = 75° and AB + AC = 13 cm.
Answers
Answer:
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Step-by-step explanation:
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Answer:
R.E.F. Image.
Given,
to construct a ΔABC where
BC=7cm,∠B=75
∘
& AB+AC=13cm.
construction steps :-
(i) Draw a line segment BC = 7 cm as a base.
(ii) Now mark ∠B=75
∘
and extend it till x.
(iii) Now, by taking radius 13 cm draw an arc from 'B' on the line of angle just projected.
(iv) Now mark it as 'D', & join C to D.
(v) Draw ⊥
lar
bisectors for DC and mark them as P & Q.
(vi) Now extend a line from 'B' to the ⊥
lar
bisector that cuts on C & D line.
(vii) Now mark that point as 'A'.
(viii) Thus, required ΔABC has been formed.
(ix) Now, try taking exactly 1/2 of the angle and mark an arc on B.
Conclusion :-
∴ The required ΔABC will BC = 7 cm,
∠B=45
∘
& AB + AC = 13 cm is constructed.
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