construct a triangle abc in which bc=7cm angle b=75degree and ab+ac=13cm
saige:
complete your question it is incomplete
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Use the sas rule because two sides are known and in angle is known
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first mark the line bc as 7 cm then construct the angle on b of 75 degree and name it as bx then mark an arc of 13 cm on bx then name that arc as y then join cy and do perpendicular bisector of cy where this perpendicular bisector meet bx name that point as a then join ca triangle abc is formed
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