Construct a triangle abc in which bc = 7cm, ∠b = 75° and ab + ac = 13 cm.
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Answered by
50
Step I: Draw a line segment BC of 7 cm. At point B, draw an angle of 75°, say ∠XBC.
Step II: Cut a line segment BD = 13 cm (that is equal to AB + AC) from the ray BX.
Step III: Join DC and make an angle DCY equal to ∠BDC.
Step IV: Let CY intersect BX at A. ΔABC is the required triangle.
Answered by
39
AB = 5.5
AC = 7.5
AB + AC = 5.5 + 7.5
=13
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AC = 7.5
AB + AC = 5.5 + 7.5
=13
hope it help you please mark as brilliant
have a great day ☺️
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