Math, asked by lahare3403, 1 year ago

Construct a triangle abc in which bc = 7cm, ∠b = 75° and ab + ac = 13 cm.

Answers

Answered by Anonymous
50

Step I: Draw a line segment BC of 7 cm. At point B, draw an angle of 75°, say ∠XBC.

Step II: Cut a line segment BD = 13 cm (that is equal to AB + AC) from the ray BX.

Step III: Join DC and make an angle DCY equal to ∠BDC.

Step IV: Let CY intersect BX at A. ΔABC is the required triangle.


Answered by Anonymous
39
AB = 5.5
AC = 7.5
AB + AC = 5.5 + 7.5
=13
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