Question

construct a triangle ABC in which BC = 8 cm, angle B= 45° and AB-AC=3.5cm.​

Answer 1

Step-by-step explanation:

Steps of Construction:

1. Draw base BC of length 8 cm

2. Now, let's draw 2 B = 45°

Check Ex 11.1, 2

on how to construct 45°

Let the ray be BX

3. Open the compass to length AB - AC = 3.5 cm.

Note: Since AB - AC = 3.5 cm is positive So, BD will be above line BC

From point B as center, cut an arc on ray BX. Let the arc intersect BX at D

4. Join CD

5. Now, we will draw perpendicular bisector of CD

6. Mark point A where perpendicular bisector intersects BD

7. Join AC

: ABC is the required triangle