Math, asked by ragini22soni, 6 months ago

construct a triangle ABC in which BC=8cm, angle AB-AC ​

Answers

Answered by durvamhatre257
0

Answer:

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Step-by-step explanation:

Draw the base BC = 8 cm.

At the point B make an angle XBC = 45°.

Cut the line segment BD equal to AB – AC (= 3.5 cm) from the ray BX.

Join DC.

Draw the perpendicular bisector, say PQ of DC.

Let it intersect BX at a point A.

Join AC.

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