Question

Construct a triangle ABC in which BC=8cm, angle B=30° and AB-AC=3.5cm​

Answer 1

Step-by-step explanation:

draw line segment bc of 8 cm

draw the 30 degree on point B by using compass and extend the line segment X to 13 cm

open the compass 23.5 cm from point B and draw Arc on b x and name it D andjoin the d ppointC

now open the compass more than half from the point B C and draw the Arc on both side and join the ARC and make a perpendicular bisector and extend it to meet the line BX and name the point of intersection as A

Answer 2

Answer:

Step-by-step explanation:

The steps of construction to be followed:

Step 1: Draw a line segment BC = 8cm and make an angle of 45^{\circ} at point B i.e., \angle XBC.

XBC

Step 2: Now, cut the line segment BD = 3.5 cm on ray BX. i.e.(AB-AC).

Step 3: Join CD and draw a perpendicular bisector of CD i.e., PQ.

XCD 45

Step 4: Let the perpendicular bisector of CD intersects BX at point A. Then,

atep 3

Step 5: Join AC, to get the required triangle \triangle ABC.