Construct a triangle ABC in which BC=8cm angle B =45 degree and AB-AC=3.5cm And justify the construction
reddyskarthee:
I need justification for construction
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Construction:
1)Draw the base BC = 8cm.
2)At B, construct an angle of 45 degree.
3)Draw the line segment till X such that angle XBC = 45 degrees.
4)Cut line segment BD equal to 3.5cm.
5)Join DC and draw a perpendicular bisector of DC.
6)Let it intersect BX at A. Join AC.
7)ABC is the required triangle.
Hope it helps ......
1)Draw the base BC = 8cm.
2)At B, construct an angle of 45 degree.
3)Draw the line segment till X such that angle XBC = 45 degrees.
4)Cut line segment BD equal to 3.5cm.
5)Join DC and draw a perpendicular bisector of DC.
6)Let it intersect BX at A. Join AC.
7)ABC is the required triangle.
Hope it helps ......
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Steps of construction
(1)draw a line segment BC=8cm
(2)At point B, draw angle CBY=45°
(3)Cut BD=3.5 from BY
(4)Join CD
(5)Draw perpendicular bisector of CD,which intersect BY at A
(6)Join C
Now,∆ABC is a required triangle
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