Question

construct a triangle ABC in which BC=8cm,angleB =45° and AB-AC =3.5cm.
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Answer 1

Step-by-step explanation:

write the steps to construct a triangle having given bc=7cm, ab-ac=1 and angleabc=45 degrees.inscribe a circle in the triangle constructed and measure its radius.use compass and ruler only.

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Raghunath Reddy

Sol; In ΔABC, given BC = ' 7' cm, ∠B = 45°. and difference of two sides AB and AC is equal to '1' cm. Case I: AB > AC Step 1: Draw the base BC = '7' cm. Step 2: Make ∠XBC = 45°. Step 3: Mark a point D on ray BX such that BD = '1' cm. Step 4: Join DC. Step 5: Draw perpendicular bisector of DC such that, it intersects ray BX at a point A. Step 6: Join AC. Thus, ABC is the required triangle. Case II: AB < AC Step 1: Draw the base BC = ' 7' cm. Step 2: Make ∠XBC = 45°. and extend ray BX in the opposite direction. Step 3: Mark a point D on the extended ray BX such that BD = '1'cm. Step 4: Join DC. Step 5: Draw a perpendicular bisector of DC such that, it intersects ray BX at point A. Step 6: Join AC. Thus, ABC is the required triangle. Now draw the perpendicular bisetors of a triangle we get point of intersection is called incenter.Draw a perpendicular line center to traingle we get radius measure.