Construct a triangle ABC in which BC=8cm, ∠B=45 Degree and AB - AC = 3 . 5 cm
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.Draw base BC of length 8cm
2.Now, let's draw ∠B=45°
.Let the ray be BX
3.Open the compass to length AB−AC=3.5cm.
Since AB−AC=3.5cm is positive.
So, BD will be above line BC
From point B as center, cut an arc on ray BX.
Let the arc intersect BX at D
4.Join CD
5.Now, we will draw perpendicular bisector of CD
6.Mark point A where perpendicular bisector intersects BD
7.Join AC
Result:∴△ABC is the required triangle.
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