Question

Construct a triangle ABC in which BC = 8cm, B = 45° and AB - AC = 3.5 cm.
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Answer 1

Answer:

Answer

1.Draw base BC of length 8cm

2.Now, let's draw ∠B=45

∘

.Let the ray be BX

3.Open the compass to length AB−AC=3.5cm.

Since AB−AC=3.5cm is positive.

So, BD will be above line BC

From point B as center, cut an arc on ray BX.

Let the arc intersect BX at D

4.Join CD

5.Now, we will draw perpendicular bisector of CD

6.Mark point A where perpendicular bisector intersects BD

7.Join AC

Result:∴△ABC is the required triangle.

Answer 2

Answer:

Here you go

Step-by-step explanation:

1.Draw base BC of length 8cm

2.Now, let's draw ∠B=45  

∘

.Let the ray be BX

3.Open the compass to length AB−AC=3.5cm.

Since AB−AC=3.5cm is positive.

So, BD will be above line BC

From point B as center, cut an arc on ray BX.

Let the arc intersect BX at D

4.Join CD

5.Now, we will draw perpendicular bisector of CD

6.Mark point A where perpendicular bisector intersects BD

7.Join AC

Result:∴△ABC is the required triangle.

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