Question

construct a triangle ABC in which bc equal to 6.1 cm ab equal to 5.7 cm and ac equal to 5.3 CM also draw a perpendicular bisector of side BC

Answer 1

Answer:ΔABC is the required triangle.

              XY is the required perpendicular bisector of side BC.

Explanation:

Given:In Δ ABC,

                     $BC=6.1cm$

                     $AB=5.7cm$

                     $AC=5.3cm$

To find:We have to draw ΔABC and also we have to draw perpendicular bisector of side BC.

Step of construction:

Step 1:Draw a line segment $BC=6.1cm$.

Step 2:From pont B,taking radius of $5.7$$cm$, draw an arc MN.

Step 3:From pont C,taking radius of $5.3$$cm$, draw an arc PQ.

Step 4:Give the name A to intersection pont of both the arc.

Step 5:Join AB and AC respectively.

Hence, the ΔABC is the required triangle.

Step 6:From point B,take radius more than half of line segment BC and draw arc upword and downword to line segment BC.

Step 7:From point C,take radius same as privious radius draw arc upword and downword to line segment BC which cut previous arcs at pont X and Y.

Step 8:Join X and Y.

Hence,XY is the required perpendicular bisector of side BC.

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