Question

Construct a triangle ABC in which BC equals to 5 cm and angle b equals to 45 degree. and ab+ ac=12 cm​

Answer 1

Answer:

★Given:-

Base BC = 7cm, angle B = 75° and

sum of two sides AB + AC = 12 cm.

★Required:-

To Construct ΔABC

★STEPS OF CONSTRUCTION:-

1. Draw a ray BX and cut off a line

segment BC 7cm; from it.

2. At B; construct angle YBX = 75°

3. With B as centre and radius = 12 cm

(because AB + AC = 12cm) draw an arc to

meet BY at D.

4. Join CD

5. Draw Perpendicular bisector PQ of CD

intersecting BD at A.

6. Join AC

Then ABC is the required triangle.

A lies on perpendicular bisector of CD.

Therefore, AC = AD

=>AB = BD - AD

=>AB=BD - AC

=AB+AC = BD = 12cm,

Which is true as given.

Step-by-step explanation:

$Hope \: it \: helps...!!$