construct a triangle ABC in which BC is equal to 3.5 CM angle b is equal to 60 degree and altitude area is equals to 2.5 cm and draw its in circle and measure its radius
Answers
Steps of construction:
1. Draw a line segment BC = 3.5 cm.
2. With B and C as a centre, draw a perpendicular bisector of BC.
3. With D as centre and radius 2.5 cm, draw an arc to cut DP at A.
4. Join AB and AC. Thus, ABC is the required triangle.
5. From points A and B draw arcs above and below the AB with a measure of more than half the length of line AB.
6. Join the points where the arcs intersect above and below the line AB.
5. From points B and C draw arcs above and below the BC with a measure of more than half the length of line BC.
6. Join the points where the arcs intersect above and below the line BC.
5. From points C and A draw arcs above and below the CA with a measure of more than half the length of line CA.
6. Join the points where the arcs intersect above and below the line CA.
7. The point where the above three lines intersect is the centre of the circle required.
8. Draw a circle.
9. Hence the circle.
Answer:
Step-by-step explanation: