Question

construct a triangle ABC in which BC is equal to 3.6 CM AP + AC is equal to 4.8 cm and angle b is 60 degree​

Answer 1

Answer:

Steps of construction:

1. Draw a line segment BC of 3.6cm.

2. At the point B, draw ∠x BC of 60o

3. With center B and radius 4.8cm, draw an arc which intersects XB at D.

4. Join DC

5. Draw the perpendicular bisector of DC which intersects DB at A.

6. Join AC Hence Δ ABCis the required triangle

Step-by-step explanation:

refer the above attachment

hope this helps you