Question

construct a triangle ABC in which BC is equal to 7 cm angle b is equal to 75 degree and a b + AC is equal to 13 cm

Answer 1

First of all, Draw BC=7cm

then make an angle 75* at the point B with the help of Compass.

Now, from the point B (75* angle), draw a line 13 CM.

Now, Draw the perpendicular bisector of that line, at which point the line bisect,

then put the name of the point a and join A to point C

That's will be your answer Dear!!!!!!

Answer 2

$\triangle ABC$ is the required triangle.

Step-by-step explanation:

Given,

Construct a $\triangle ABC$ in which $BC=7\ cm$, $\angle B=75°$ and $AB-AC=13\ cm$

Following steps:

• Draw the line segment $BC=7\ cm$ and at point $B$, make an angle of $75°$ like $\angle XBC=75°$
• Cut the line segment $BD=13\ cm$ ($AB-AC=13\ cm$) on ray $BX$
• Join $DC$ and draw the perpendicular bisector $PQ$ of $DC$
• Let, It intersect $BX$ at point $A$. Join $AC$.

Now, $\triangle ABC$ is the required triangle.